Question

Width of center peak (cm)	1.6
Width of slit for a single peak	2.3

1. Was your prediction (constructed in Pre-Lab Question 2) about the single slit results correct? How does it compare the observed results?

2. What happened to the diffraction pattern as you increased the width of the slit?

3. If you shined the light through a door, would you observe a diffraction pattern? Why or why not?

Answer 1

Solution given below :-
2. In diffraction pattern, fringe width is given as beta = D lambda / a, where a is the slit width, so on increasing slit width, fringe width reduces and brightness of maxima increases.

3. Condition necessary for diffraction to take place is that the width of obstacle should be comparable to the wavelength of light wave which is of the order of Angstrom, so diffraction will not be observed through a door as its width is not comparable with the width of wavelength of light.