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A small sphere of mass m = 6.70 g and charge q1 = 27.8 nC is...

A small sphere of mass m = 6.70 g and charge q1 = 27.8 nC is attached to the end of a string and hangs vertically as in the figure. A second charge of equal mass and charge q2 = −58.0 nC is located below the first charge a distance d = 2.00 cm below the first charge as in the figure.
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Answer #1

(a) The string has to support the weight of m1 and the force of attraction between the two charges (F)
W = mg = 0.0067kg x 9.80N/kg = 0.0656 N
F = k.q1.q2 / d² = (9.0*10^9)(27.0*10^-9C)(58.0*10^-9C) / (0.02m)² = 0.0352 N

Tension = (0.0656 + 0.0352)N .. .. ►T = 0.101 N

b) Max electric force = 0.18 - W = (0.18 - 0.0656) = 0.1144 N
F(max) = k.q1.q2 /d²
d² = k.q1.q2 / F(max) ..
d² = (9.0*10^9)(27.0*10^-9)(58.0*10^-9) / 0.106 = 1.23*10^-4 .. ►d(min) = 1.10cm

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