Question

The moon has an angle of 0.5 degrees in the terrestrial telescope lens, where the illuminance is 0,25x10E5 lux to the normal incidence.

The focal lengths of the telescope lens and the ocular lens are 20 cm and 5cm, respectively.

Calculate the diameter of the moon in the "nearest point" of the 25 cm and the illuminance of the image of the moon.

Answer #1

The telescope at a small observatory has objective and eyepiece
focal lengths respectively of 18.2 m and 12 cm. If this telescope
is used to view a 2000 m diameter lunar crater on the surface of
the moon 3.77 108 m from the surface of the Earth, determine the
following.
(a) angular magnification of the telescope
(b) size of the first image ____ m
(c) length of the barrel of the telescope _____ m
(d) angle subtended at the unaided...

Exercises
1. How is the image formed by the mirror different from the
lenses ?
Exercises: Problem Solving
1. The focal point is found 20 cm from a double concave lens
where an object is placed 12 cm. Find the image distance.??
2- A 2.8 cm diameter coin is placed 25 cm from a double concave
lens with focal length of -12 cm. Find the image distance and
diameter of the image??
3. An object that is 8 cm high...

What is the change in length of a metal rod with an original
length of 4 m, a coefficient of thermal expansion of 0.00002/ ° C,
and a temperature change of 30° C?
1.
2.4 mm
2.
12 mm
3.
1.2 mm
4.
24 mm
Determine the number of electrons passing through a point in the
wire in 8 minutes when the current is 10 A.
a.
3 * 1016 electrons
b.
none of these
c.
4,800 electrons
d.
1.6...

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