Question

A 2000 kg car reaches the top of a 100 meter high hill at A with...

A 2000 kg car reaches the top of a 100 meter high hill at A with a speed

vA = 40 m/s

. What is the speed

vB

at the top of the 150 m high hill at B if all sources of friction do work equal to −500,000 J on the car as it coasts in neutral from A to B?

13.5 m/s

11.0 m/s

18.6 m/s

10.1 m/s

14.9 m/s

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Homework Answers

Answer #1

Gravitational acceleration = g = 9.8 m/s2

Mass if the car = M = 2000 kg

Height of hill at point A = HA = 100 m

Speed of the car at point A = VA = 40 m/s

Height of the hill at point B = HB = 150 m

Speed of the car at point B = VB

Work done by friction on the car as it travels from point A to B = W = -500000 J

By conservation of energy the potential and kinetic energy of the car at point A plus the work done by friction on the car is equal to the potential plus kinetic energy of the car at point B.

VB = 11.0 m/s

Speed of the car at the top of the 150 m high hill at B = 11.0 m/s

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