Question

A stone is dropped from rest into a well. The sound of the splash is heard exactly 2.20 s later. Find the depth of the well if the air temperature is 8.0

Answer 1

when the stone strikes the water s sound wavw is PRODUCED .THE SOUND wave will have travelled a distance

speed of the sound v = 331+(0.6*t) = 331+(0.6*8) = 335.8 m/s

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time taken by the stone to reach the water

h = = 0.5*g*t1^2======> t1 = sqrt(2h/g)

time taken by the sound to reach to the top = t2 = h/v = h/335.8

t1 + t2 = t

sqrt(2h/g) + t2 = t

sqrt(2h/g) + h/v = 2.2

sqrt(2h/g) = 2.2- h/v

(2h/g) = (2.2- h/v ) ^2

h/4.9 = (2.2- h/335.8)^2

h = 22.3 m   <---answer