Question

1.Four wires come from a node. Three of those wires have current entering the node. What can you say about the fourth wire?

2.You see a drawing of a circuit with multiple paths. How does the voltage difference around a longer path compare to the voltage difference around a shorter path?

3.Describe the behavior of an empty capacitor when an initial voltage is applied?

4.Draw a circuit that has one battery, one resistor, one capacitor, and one inductor. Make sure the circuit has at least one element in series with something and one element in parallel with something. Draw a simplified version of the circuit after it has been connected for a long time.

you do not have to write a lot

only a sentance is enough

Answer 1

1) If three of the four wires have current entering the node then it is obvious that the fourth wire will have current equal to the sum of the other three currents and it must be leaving the node.

It is because Kirchhoff's node law says that the sum of the current entering a node must be equal to the sum of the current leaving it.

2) They are the same.

3) AT the initial stage, capacitor behaves as a short circuit.

If three of the four wires have current entering the node then it is obvious that the fourth wire will have current equal to the sum of the other three currents and it must be leaving the node.