Question

A student drops a 0.29-kg piece of steel at 42 ∘C into a container of water at 22 ∘C. The student also drops a 0.54-kg chunk of lead into the same container at the same time. The temperature of the water remains the same.

Part A

Part complete

Was the temperature of the lead greater than, less than, or equal to 22 ∘C?

Equal to

Less than

Greater than

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Correct

Part B

What was the temperature of the lead?

Express your answer to two significant figures and include appropriate units.

negative −20°cc

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Answer 1

here,

mass of steel peice , m1 = 0.29 kg

mass of lead chunk , m2 = 0.54 kg

a)

as the temprature of water remains the same

the final temprature of lead and steel is also same

so, heat lost by steel peice = heat gained by lead chunk

as the lead chunk gains heat

the initial temprature of lead chunk is less than 22 degree C

b)

let the initial temprature of lead be T2

using conservation of heat energy

heat lost by steel peice = heat gained by lead chunk

m1 * C1 * ( 42 - 22) = m2 * C2 * ( 22 - Ti)

0.29 * 502 * ( 20) = 0.54 * 125 * ( 22 - Ti)

Ti = - 21.1 degree C