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A skater is initially spinning at a rate of 19.70 rad/s with a rotational inertia of...

A skater is initially spinning at a rate of 19.70 rad/s with a rotational inertia of 2.540 kg·m2 when her arms are extended. What is her angular velocity after she pulls her arms in and reduces her rotational inertia to 1.620 kg·m2?

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Answer #1

Since Rotational Inertia or Moment of Inertia is

Now in the above we case must remember that angular must be conserved when she pull her arms, So, if angular momentum is conserved, and one factor like I changes, the other factor ( in this case) must change to compensate.

So  

Initial angular momentum

Now the Final Momentum will also be same but here rotational inertia changes so to conserve the angular momentum , spinning rate must increase .

Therefore we can say that

The angular momentum when she her arms off is  

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