Question

A grinding wheel 0.27 m in diameter rotates at 2700 rpm .

A) Calculate its angular velocity in rad/s.

w =

B)

What is the linear speed of a point on the edge of the grinding wheel?

Express your answer to two significant figures and include the appropriate units.

v=

C) What is the acceleration of a point on the edge of the grinding wheel?

Express your answer to two significant figures and include the appropriate units.

aR =

Answer 1

The expression for the angular velocity is as follows w = 2pi/t

Convert 2700 rpm into seconds as follows

T = 2700/60 s

Thus the angular velocity is as follows

Angular velocity w = 282.74 rad/s

The relation between the angular velocity and the linear speed is follows

Solve for V

V = 282.74 rad/s

Linear speed v = 38.16m/s

The relation between acceleration and angular velocity a = w²r

Solve for a

Solve for V

V = 282.74 rad/s

Linear speed v = 38.16m/s

The relation between acceleration and angular velocity a = w²r

Solve for a