Question

You arrange two identical charges along the x-axis at positions (-3.0,0) and (3.0,0), with distances measured in centimeters. You've set things up so that the origin of your coordinates lies at the midpoint between the charges. You measure the electric force acting on the charge on the right and find it has a magnitude of 24574.3 N. You want to deduce the electric field vector that is acting on the right-hand charge.

Answer #1

Position of left charge q = (-3.0,0)

Position of right charge q = (3.0, 0)

Distance between charges r = 6 cm = 0.06 m

Electric force F acting on right charge = F = 24574.3 N

It must be acting towards right direction as charges are of same nature and they will repel each other

F = k q^2/r^2

24574.3 = (9 x 10^9)q^2/(0.06)^2

q = 9.9 x 10^-5 C

Electric field vector acting on right hand charge = E = F/q

E = 24574.3/(9.9 x 10^-5) = **2.48 x 10^8 N/C (towards
right direction)** [ Electric field has the same direction
as electric force]

Three point charges are aligned along the x axis as
shown in the figure below.
Three point charges lie along the x-axis in the
x y coordinate plane.
A charge of −4.00 nC is 0.500 m to the left of the origin.
A charge of 5.00 nC is at the origin.
A charge of 3.00 nC is 0.800 m to the right of the origin.
Find the electric field at the following positions.
(a) (3.00, 0)
=
(b) (0, 3.00)
=

Two point charges are fixed in place along the x axis
as shown in the figure above. The charge Q1=-3
μμC is located at the origin. The charge Q2=4
μμC is a distance a = 0.46 m to the right of the
origin.
1)
Calculate the x component of the
electric field at point P a distance
h=0.32 m above the origin.
Ex = -0.115 × 106 N/C
Ex = -0.094 × 106 N/C
Ex = 0.264 × 106 N/C...

Two positive charges of 1.6e-10 C are placed on the x axis at
distances +40 cm and -40 cm from the origin, respectively. A third
positive charge of 3.5e-11 C can be moved along the y axis. At what
value of y the electrostatic force on the third charge is
maximal?

Two positive charges of 1.7e-10 C are placed on the x axis at
distances +14 cm and -14 cm from the origin, respectively. A third
positive charge of 5.5e-11 C can be moved along the y axis. At what
value of y the electrostatic force on the third charge is
maximal?

Two
equal charges of 3.00 x 10^-6 C lie along the x-axis: one is at the
origin, and the other is 2.0 m from the origin. Find the magnitude
and direction of the electric field at a point on the y-axis 0.25 m
from the origin.

GOAL Use the superposition principle to calculate the electric
field due to two point charges. Consider the following
figure.
The resultant electric field at P equals the
vector sum 1 + 2, where 1 is the
field due to the positive charge q1and
2 is the field due to the negative charge
q2.Two point charges lie along the
x-axis in the x y-coordinate plane.
Positive charge q1 is at the origin, and
negative charge q2 is at (0.300 m, 0). Point...

Two point charges are placed along a horizontal axis with the
following values and positions: +3.8 µC at x = 0 cm and −7.6 µC at
x = 20 cm. At what point along the x axis is the electric field
zero?

three charges are aligned on the x axis. Q1 (-.500micro c) is
at the origin. q2 (-1.00micro coulomb) is at 30nm to the left of
the origin. Q3(+4 micro Coulomb) is at 15. nm to the right of the
origin. find total electric force acting on charge at origin.

Three point charges exist along the x-axis. A charge of +e is at
the origin, a charge of -4 e exists 2 μm to the left of the origin,
and another charge of +4 e exists 2 μm to the right of the origin.
Calculate the net force on the rightmost charge.

a charge of 3.4 microC is located at 0.44m along the positive
x-axis. a second charge of -5.99microC is at the origin. what is
the magnitude of the electric field due to these charges at a
location on the y axis of 0.61m. please show work

ADVERTISEMENT

Get Answers For Free

Most questions answered within 1 hours.

ADVERTISEMENT

asked 7 minutes ago

asked 28 minutes ago

asked 33 minutes ago

asked 33 minutes ago

asked 38 minutes ago

asked 56 minutes ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago