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You are pulling a 11.12 kg object with 26 N force which is oriented at 26...

  1. You are pulling a 11.12 kg object with 26 N force which is oriented at 26 degree with ground. What is acceleration?


You are pulling a 36.9 kg object with 11.3 N force which is oriented at 17 degree with ground. What is acceleration? Assume kinetic frictional coefficient mu_k = 0.01.
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Answer #1

You are pulling a 11.12 kg object with 26 N force which is oriented at 26 degree with ground. What is acceleration?

since there is no friction so

Fnet =m*a

a = Fnet/m = 26*cos26 /11.12 =2.1015 = 2.1 m/s2

You are pulling a 36.9 kg object with 11.3 N force which is oriented at 17 degree with ground.What is acceleration? Assume kinetic frictional coefficient mu_k = 0.01.

Fnet =ma

F*cos17 -μk*N =ma , N = mg -Fsin17 so

F*cos17 -μk ( mg -Fsin17) = ma

11.3*cos17 - 0.01* ( 36.9*9.8-11.3*sin17) = 36.9 *a

 
a≈0.195747   m/s2
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