You are pulling a
11.12
kg object with
26
N force which is oriented
at 26
degree with ground.
What is acceleration?
You are pulling a 11.12 kg object with 26 N force which is oriented at 26 degree with ground. What is acceleration?
since there is no friction so
Fnet =m*a
a = Fnet/m = 26*cos26 /11.12 =2.1015 = 2.1 m/s2
You are pulling a 36.9 kg object with 11.3 N force which is oriented at 17 degree with ground.What is acceleration? Assume kinetic frictional coefficient mu_k = 0.01.
Fnet =ma
F*cos17 -μk*N =ma , N = mg -Fsin17 so
F*cos17 -μk ( mg -Fsin17) = ma
11.3*cos17 - 0.01* ( 36.9*9.8-11.3*sin17) = 36.9 *a
a≈0.195747 m/s2
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