Question

Two blocks are connected by an ideal cord that does not stretch, the cord passes over...

Two blocks are connected by an ideal cord that does not stretch, the cord passes over an ideal pulley. The weight of the heavier block is 1.2 N larger than the weight of the lighter block. The lighter block has the acceleration 4.4 m/s2 up. What is the weight of the heavier block?

Homework Answers

Answer #1

Gravitational acceleration = g = 9.81 m/s

Mass of the lighter block = m1

Mass of the heavier block = m2

Tension in the cord = T

Acceleration of the blocks = a = 4.4 m/s2

The weight of the heavier block is 1.2 N larger than the weight of the lighter block.

(m2 - m1)g = 1.2 N

m2 - m1 = 0.1223

From the free body diagram,

T - m1g = m1a

T = m1g + m1a

m2g - T = m2a

m2g - m1g - m1a = m2a

(m2 - m1)g = (m1 + m2)a

(m1 + m2)(4.4) = 1.2

m1 + m2 = 0.2727

m2 - m1 = 0.1223

Adding these two equations we get,

2m2 = 0.395

m2 = 0.1975 kg

Weight of the heavier block = m2g = (0.1975)(9.81) = 1.937 N

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