Question

A diver of weight 450 N stands at the end of a diving board of
length *L* = 4.1 m and negligible mass (the figure). The
board is fixed to two pedestals separated by distance *d* =
1.8 m. Take the upward direction to be positive. Of the forces
acting on the board, what are **(a)** the force from
the left pedestal and **(b)** the force from the right
pedestal?

Answer #1

Since Figure is not given, So I'm assuming that

F1 = Force on left pedestals at x = 0

F2 = Force on right pedestals at x = d

W = Weight of diver, located at x = L

Now Using force balance in vertical direction

Fnet = F1 + F2 - W = 0

F1 + F2 = W

Using torque balance about right pedestals

Net torque = F1*d + W*(L - d) = 0

from above equation

F1 = -W*(L - d)/d

Using given values:

W = 450 N

L = 4.1 m & d = 1.8 m

So,

**F1 = -450*(4.1 - 1.8)/1.8 = -575 N**

Magnitude of F1 = 575 and negative sign means force F1 is downward

Part B.

F1 + F2 = W

F2 = W - F1

**F2 = 450 - (-575) = +1025 N**

**Positive sign means force is upward.**

**Please Upvote.**

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