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A projectile is fired at v0=342.0 m/sv0=342.0 m/s at an angle of θ=69.9∘θ=69.9∘, with respect to...

A projectile is fired at v0=342.0 m/sv0=342.0 m/s at an angle of θ=69.9∘θ=69.9∘, with respect to the horizontal. Assume that air friction will shorten the range by 28.1%28.1%. How far will the projectile travel in the horizontal direction, RR?

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Answer #1

Given:

Initial launch velocity,

Launch angle,

--------

First, find the range while ignoring the air friction.

Use formula

=================

Given that the air friction will shorten the range by 28.1%

So Required Range,

ANSWER:

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