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Batman (mass = 87.0 kg) jumps straight down from a bridge into a boat (mass =...

Batman (mass = 87.0 kg) jumps straight down from a bridge into a boat (mass = 677 kg) in which a criminal is fleeing. The velocity of the boat is initially +9.47 m/s. What is the velocity of the boat after Batman lands in it?

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Answer #1

We have to apply momentum conservation to find the final velocity.

Take the initial velocity of boat in x direction.

Initial momentum of batman (in x axis) =0.

Initial momentum of boat in x axis = 667*9.47 kg-m/sec. =6316.49 kg-m/sec.

Consider the batman and the boat as single isolated system.

Total momentum of the system before batman jumps =Momentum of boat+momentum of batman= final momentum.

Total momentum of the system before batman jumps =Momentum of boat+momentum of batman= final momentum.

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