Question

A satellite of mass *m* = 2.00 ×103 kg is launched into a
circular orbit of orbital period *T* = 4.00 hours. Newton's
gravitational constant is *G* = 6.67 ×10−11 N∙m2/kg2, and
the mass and radius of the Earth are respectively *M*⨁ =
5.97 ×1024 kg and *r*⨁ = 6.37 ×106 m. Answer the following
questions.

What is the total mechanical energy (kinetic energy + potential energy) of the satellite in orbit? Take the gravitational potential energy of the satellite when it is infinitely far away from the Earth to be zero.

What was the launch speed *v*0 of the satellite? Neglect
the kinetic energy of the satellite due to the rotation of the
Earth before launch.

If the satellite is launched straight up instead of into orbit
with the launch speed you found in question 7, what is the maximum
distance from the Earth's center *r*max that the satellite
will reach?

Answer #1

A satellite of mass 1525 kg is in circular orbit around Earth.
The radius of the orbit of the satellite is equal to 1.5 times the
radius of Earth (RE = 6.378*106 m, ME = 5.98*1024 kg, G =
6.67*10-11 Nm2/kg2). (a) Find the orbital period of the satellite?
(b) Find the orbital (tangential) velocity of the
satellite. (c) Find the total energy of the
satellite?

(part 1 of 3) A satellite of mass 398 kg is launched from a site
on the Equator into an orbit at 544 km above Earth’s surface. If
the orbit is circular, what is the satellite’s speed in orbit? The
gravitational constant is 6.67259 × 10^−11 N · m2/kg2 , the mass of
the earth is 5.98 × 10^24 kg and its radius is 6.37 × 10^6 m.
Answer in units of m/s.
(part 2 of 3) What is the...

A 345 kg satellite is orbiting on a circular orbit 8955 km above
the Earth's surface. What is the gravitational acceleration at the
location of the satellite? (The mass of the Earth is
5.97×1024 kg, and the radius of the Earth is 6370
km.)?

NASA launches a satellite into orbit at a height above the
surface of the Earth equal to the Earth's mean radius. The mass of
the satellite is 830 kg. (Assume the Earth's mass is 5.97 1024 kg
and its radius is 6.38 106 m.) (a) How long, in hours, does it take
the satellite to go around the Earth once? h (b) What is the
orbital speed, in m/s, of the satellite? m/s (c) How much
gravitational force, in N,...

A satellite is launched to orbit the Earth at an altitude of
2.20 * 10^7 m for use in the Global Positioning system (GPS). Take
the mass of the Earth to be 5.97 * 10^24 kg and its radius 6.38 *
10^6 m. (a) What is the orbital period of this GPS satellite? (b)
With what speed does it orbit the Earth?

A satellite is set to orbit at an altitude of 20200 km above the
Earth's surface. What is the period of the satellite in hours?
(Earth radius 6.378×1066.378×106 m, Earth mass 5.97×10245.97×1024
kg, Universal Gravitational constant
G=6.67×10−11m3kg−1s−2G=6.67×10−11m3kg−1s−2 ).

A 160 kg satellite is orbiting on a circular orbit 7655 km above
the Earth's surface. Determine the speed of the satellite. (The
mass of the Earth is 5.97×1024
kg, and the radius of the Earth is 6370 km.)
(in km/s)

A satellite of mass 350 kg is in a circular orbit around the
Earth at an altitude equal to the Earth's mean radius.
(a) Find the satellite's orbital speed.
m/s
(b) What is the period of its revolution?
min
(c) Calculate the gravitational force acting on it.
N

(a) Calculate the orbital speed of a satellite that orbits at an
altitude h = one Earth radius above the surface of the Earth. (b)
What is the acceleration of gravity at this altitude? (G = 6.67 x
10-11 N.m2 /kg2 , ME = 5.97 x 1024 kg, RE = 6.37 x 106 m)

A satelite in a circular orbit has an orbital period of 189
minutes . On Earth the satelite weighs 980 N. The earth's mass is
5.97 × 1024 kg, its equatorial radius is 6.3 × 106 m, and G = 6.67
× 10−11 N • m2/kg2.
How far is the satellite above the earths surface?
How far is it from the earths surface?
If the weight of the satelite on Earth were 8820 N instead of
the 980 N given...

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