A 1900-kg car experiences a combined force of air resistance and friction that has the same magnitude whether the car goes up or down a hill at 27 m/s. Going up a hill, the car’s engine produces 35.10 kW more power to sustain the constant velocity than it does going down the same hill. Calculate at what angle the hill is inclined above the horizontal.
Find the force of engine in terms of combined force of resistance and friction and the component of gravitational force along the incline while going up and down and use that to find the required angle as shown below
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