Question

a projectile is launched upward at an angle. what should this angle be with respect to the horizontal in order for the projectile to travel the farthest distance? explain why

Answer #1

Solution-

Horizontal range of a projectile given by R = v^2 sin 2θ /
g

The range must be maximum for farthest distance to travel

Therefore, R = R max

For R = Rmax, sin 2θ = 1 [ since the maximum value of sine function
= 1 ]

sin 2θ = sin 90

2θ
= 90

Angle of projection, θ = 45 degrees

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