Question

a projectile is launched upward at an angle. what should this angle be with respect to the horizontal in order for the projectile to travel the farthest distance? explain why

Answer 1

Solution-

Horizontal range of a projectile given by R = v^2 sin 2θ / g
The range must be maximum for farthest distance to travel
Therefore, R = R max
For R = Rmax, sin 2θ = 1 [ since the maximum value of sine function = 1 ]
                         sin 2θ = sin 90
                               2θ = 90
Angle of projection, θ = 45 degrees