Question

question: A particle with charge 8.00×10^{−19} C is
placed on the *x* axis in a region where the electric
potential due to other charges increases in the +*x*
direction but does not change in the *y* or *z*
direction.

part A: The particle, initially at rest, is acted upon only by
the electric force and moves from point *a* to point
*b*along the *x* axis, increasing its kinetic energy
by 1.60×10^{−18} J . In what direction and through what
potential difference *V**b*−*V**a* does
the particle move?

A. The particle moves to the left through a potential
difference of Vb−Va= 2.00 V
. |

B. The particle moves to the left through a potential
difference of Vb−Va= -2.00
V |

C. The particle moves to the right through a potential
difference of Vb−Va= 2.00 V
. |

D. The particle moves to the right through a potential
difference of Vb−Va= -2.00 V
. |

E. The particle moves to the left through a potential
difference of Vb−Va= 20.0 V
. |

F. The particle moves to the right through a potential
difference of Vb−Va= -20.0 V
. |

Part B :If the particle moves from point *b* to point
*c* in the *y* direction, what is the change in its
potential energy, *U**c*−*U**b*?

+ 1.60×10^{−18} J

− 1.60×10^{−18} J

0

Answer #1

Ans)

Part A)

change in electrical potential energy = -(change in kinetic
energy)

q(ΔV) = -ΔK

q(Vb-Va) = -ΔK

given charge q=8.00x10^{-19}c

(8.00x10^{-19} C)(Vb - Va) =
-(1.60x10^{-18}J)

Vb-Va = [ -(1.60x10^{-18}J)] /(8.00x10^{-19} C)

Vb-Va=-2.00V

This is because if no forces other than the electric force acts on
a positively charged particle, the particle

always moves towards a point a lower potential

so the particle moves to the left through a potential difference of Vb-Va=-2.00V

Therefore the answer is option b

Part B)

Every time a charged particle moves along a line of constant potential

its potential energy remains constant and the electric field does not work on the particle.

so no potential energy

that is Uc-Ub=0J

A particle with charge 1.60×10−19 C is placed on the
x axis in a region where the electric potential due to
other charges increases in the +x direction but does not
change in the y or z direction.
The particle, initially at rest, is acted upon only by the
electric force and moves from point a to point b
along the x axis, increasing its kinetic energy by
1.44×10−18 J . In what direction and through what
potential difference Vb−Va...

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a) A particle with a charge of -4.0 μC and a mass of 4.9 x
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a)
A particle (charge = 70 μC) moves in a region where the only
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Determine the electric potential difference, VB - VA. (in
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E→=(4iˆ+3jˆ)E→=4i^+3j^A- VB? (in Volts)

An electron is at the origin.
(a) Calculate the electric potential
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V
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What is the potential difference VB -
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V
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(a) Determine the x and y components of the
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Ex_____
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(a) Determine the x and y components of the
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Ex
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