Question

A train going from one station to the next on a straight section of track accelerates from rest at 1.1 m/s^2 for 20 s. Then it slows down at 2.2 m/s^2 until it stops at the station.

What is the speed of the train after 20 seconds?

What is the distance between the 2 stations?

Answer 1

Here, for stopping the train from one station to another

let the stopping time is t2

1.1 * 20 = 2.2 * t2

t2 = 10 s

speed of train after 20 s = a * t

speed of train after 20 s = 1.1 * 20

speed of train after 20 s = 22 m/s

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distance between stations = distance travelled while accelertation + distance travelled while deceleration

distance between stations = 0.50 * 1.1 * 20^2 + 0.50 * 2.2 * 10^2

distance between stations = 330 m

the distance between the stations is 330 m