Question

A man of mass m is standing on a scale inside an elevator. Which is the...

A man of mass m is standing on a scale inside an elevator. Which is the correct Newton’s 2nd Law equation for the forces acting on the man as the elevator starts to go down with an acceleration of magnitude a?

Group of answer choices

N + mg = ma

mg – N = ma

N – mg = 0

N – mg = ma

Homework Answers

Answer #1

Here, in this question we have used Newton's second law of motion to find the correct equation of motion.

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A person rides in an elevator while standing on a scale. When the elevator is traveling...
A person rides in an elevator while standing on a scale. When the elevator is traveling upward but slowing down at a certain rate, the scale shows 450 N. When the elevator is going down and slowing down at the same rate, the reading of the scale is 300 N. What was the magnitude of the elevator’s acceleration in both case?
A man stands on a scale in an elevator that has an upward acceleration a. The...
A man stands on a scale in an elevator that has an upward acceleration a. The scale reads 972 N. When he picks up a 19.4 kg box, the scale reads 1211 N. 1) Find:The mass of the man. mman 2)The weight of the man. Wman = 3)The acceleration a. a =
You stand on a scale in an elevator (calibrated to measure mass). a. Draw a picture...
You stand on a scale in an elevator (calibrated to measure mass). a. Draw a picture of you and all forces acting on you. b. Draw a new picture of the scale and all forces acting on it (when you are on top of it). c. How are the normal forces on you from the scale and on the scale from you related? d. Convert weight into mass (1.00 kg = 2.20 lbs), use this mass for all calculations. e....
Physics Lab: Calculating the Acceleration of an Elevator? When not moving the scale read 77.1kg. The...
Physics Lab: Calculating the Acceleration of an Elevator? When not moving the scale read 77.1kg. The scale read 84.4 kg when the elevator moved from the 2nd to the 1st floor, 85.3 kg when moving from the 1st to the ground floor, and 72.6 kg when both moving from the ground to the 1st floor and the 1st to the 2nd. I need to find the acceleration of the elevator going down and up using the formula a=(Fn-mg)/m. I understand...
Sarah stands on a bathroom scale inside an elevator. Sarah's mass is 50 kg. What does...
Sarah stands on a bathroom scale inside an elevator. Sarah's mass is 50 kg. What does the scale read in Newton if the elevator moves upward with constant velocity of 1.5 m/s.? What does the scale read if the elevator moves upward for a short period of time with the acceleration of 2 m/s2? draw a free body diagram and show your work. (20 points) (g=9.8 m/s2 ) Please draw the diagram!
1. For a stationary ball of mass m = 0.200 kg hanging from a massless string,...
1. For a stationary ball of mass m = 0.200 kg hanging from a massless string, draw arrows (click on the “Shapes” tab) showing the forces acting on the ball (lengths can be arbitrary, but get the relative lengths of each force roughly correct). For this case of zero acceleration, use Newton’s 2nd law to find the magnitude of the tension force in the string, in units of Newtons. Since we will be considering motion in the horizontal xy plane,...
1. A mass of 2.8 kg is suspended from the ceiling of an elevator by a...
1. A mass of 2.8 kg is suspended from the ceiling of an elevator by a rope. What is the tension in the rope when the elevator moves in the following ways? (a) accelerates upward at 1.2 m/s2 0 N 24.1 N 27.4 N 30.8 N (b) accelerates downward at 1.2 m/s2 0 N 24.1 N  27.4 N 30.8 N 2. A toboggan with two riders has a total mass of 88.0 kg. A third person is pushing the toboggan with...
ELEVATORS A100 kg person is standing on a scale in an elevator. Starting from rest, the...
ELEVATORS A100 kg person is standing on a scale in an elevator. Starting from rest, the elevator descent attaining a downward speed of 2.0m/s in 4sec. it then travels with a constant speed during the next 2 sec. finally the elevator undergoes a uniform acceleration I. the positive y direction for 10 sec and comes to rest g=9.8m/s^2 what is the scale reading 1. before the elevauor starts 2. during 1st accel 3,while constant 4. during the time slowing down
You are in an elevator which accelerates upward. You are standing on the scale. Your normal...
You are in an elevator which accelerates upward. You are standing on the scale. Your normal weight is w = 645 N . A) Make a free-body diagram of your body if the elevator has an acceleration a = 2.32 m/s2 . B)Find the scale reading with the conditions given in part (A)? C)If you start holding a 3.90 kgkg package by a light vertical string, make a free-body diagram of the package. Draw the force vectors with their tails...
1. A 55.0 kg person rides in an elevator while standing on a scale. The elevator...
1. A 55.0 kg person rides in an elevator while standing on a scale. The elevator is traveling downward but slowing down at a rate of 1.5 m/s^2. The reading on the scale is closest to... 2. A batter hits a 130-gramm baseball that was approaching him horizontally at 45.0 m/s and, as a result, the ball leaves the bat at 45.0 m/s in the direction of the pitcher. What is the magnitude of the impulse delivered to the baseball?...