From the data given
diameter of the CD = 12 cm = 0.12 m
initial radius where the laser starts is r1 = 2.5 cm and
final radius is r2 = 5.8 cm
and the space between the centers of neighbouring spiral windings is d = 1.6*10^-6 m
the area covered is A = pi(r2^2-r1^2)
A = pi(0.058^2-0.025^2) m^2
and the toal length is l = A/d
l = pi(0.058^2-0.025^2) / (1.6*10^-6) m = 5378 m
given the velocity is v = 1.2 m/s
time taken is t = l/v = 5378 /1.2 s = 4481.67 s
t =4481.67 /60 min
t = 74.6945 min
t = 1.245 hr
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