Question

a) How does doubling your velocity affect your kinetic energy?

b) How does trippling your velocity affect your kinetic energy?

c) If your velocity doubles, how much further will it take you to stop when you apply a force?

d) If your velocity triples how much further will it take you to stop when you apply a force?

Answer #1

EDIT:

Typed version of the answer:

KE is given by:

K = 1/2*m*v^2

Thus KE is directly proportional to the square of the velocity.

Thus:

(a) KE increases by (2)^{2} = 4 times

(b) KE increases by (3)^{2} = 9 times

Now, we have, v = at

=> t = v/a

Thus t is directly proportional to v. Thus we have:

(c) It will take twice the time.

(d) It will take thrice the time.

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