Question

The initial path of a rocket is 40° above the horizontal, and the horizontal component of the rocket's velocity is 320 m/s. What is he initial vertical component of the rocket's velocity?

Answer 1

Solution:

For a projectile motion in the problem,

Given,

v_x = 320 m/s and = 40^o

Using the relations of projectile, '

v_x = v_oCos = 320

v_o = 320/Cos40^o = 417.73 m/s.

The vertical component of rocket,

v_y = v_oSin = 417.73*Sin40^o

= 268.5 m/s.

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