Question

Consider that the clarifier linear flow through velocity is set at 0.02m/s to prevent scouring.Estimate the specific gravity of the particle using the following information

diameter of particle = 200 m (micro meter)

darcy weisbach friction factor = 0.03

velocity = 0.02m/s

B(beta)=0.06

g = 9.81m/s^-2

density of water = 1000 kg/m^-3

Answer #1

Given,

please check whether the value is given in micro meter or mini meter, if it is mini meter then please

replace with 10^{-6}.

v = 0.02 m/s

g = 9.81 m/s^{2}

and

and viscostiy of water = = 1.31 × 10−6 m^{2}/ s.

we know the specific gravity is calulated by the following formula,

But here velocity is reached the point and become critical velocity. critical velocity is given by:

where S is the specific gravity of the particle. hence solve for S by squarring both sides.

S - 1 = 1.2742 x 10^{-5}

S = 1.00001274

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