A slab of copper of thickness b = 1.190 mm is thrust into a parallel-plate capacitor of C = 2.00×10-11 F of gap d = 5.0 mm, as shown in the figure; it is centered exactly halfway between the plates. How much work is done on the slab as it is inserted? Not sure if this info is helpful but the capacitance after the slab is introduced is calculated to be 2.62×10-11 F
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