An airplane flies due north with an air speed of260 km/h . A steady wind at 65 km/h blows eastward. (Air speed is the speed relative to the air.)
What is the plane’s ground speed (vpg)?
If the pilot wants to fly due north, what should his heading be?
In this the given the speed of the airplane relative to air is 260km/h duenorth
therefore vpa = 260km/h due north
then vpa,x = 0km/h
vpa,y = 260km/h
also given speed of wind relative to ground is 65km/s dueeast.
therefore....the solution are....
vag = 65km/h due east
then vag,x = 65km/h
vag,y = 0km/h
vpg,x = vpa,x +vag,x
Substitute the value.....
= 0km/h + 65km/h
And vpg,y = vpa,y +vag,y
=260km/h + 0km/h
vpa = sqrt[(65km/h)2 +(260km/h)2]
direction is tan-1(260/65) = 75.9otoward north of east
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