Question

A hot-air balloon is rising straight up with a speed of 4 m/s. A ballast bag is released from rest relative to the balloon at 13 m above the ground. How much time elapses before the ballast bag hits the ground?

Answer #1

**Given**

**velocity of the ballon is u = 4 m/s**

**height of the ballon when the ballast bag released is h
= 13 m**

**t =?**

**when the ballast bag is released from rest , with
respect to the ground the bag is moving with velocity 4
m/s**

**and hits the ground after t s**

**from equations of motion**

**V^2 - u^2 = 2as**

**v^2 = u^2+2as**

**v^2 = 4^2+2*9.8*13**

**v = 16.45 m/s**

**for time t**

**using the equations of motion v = u+at**

**v = -u+gt**

**16.45 = -4+9.8*t**

**solving for t**

**t = 2.0867 s**

**so time elapses before the ballast bag hits the ground
is 2.0867 s**

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