A forensic scientist (CSI) is trying to find a weapon thrown off a bridge into the lake. Assume it is thrown horizontally and it sinks straight down once it hits the water. The bridge height is 15 meters and a normal throwing speed is 23 m/s. How far from the bridge should you search? Give the answer to the nearest whole number in meters.
Assuming it is thrown horizontally we have velocity in x-direction as
vx = 23 m/s
For the vertical motion, we have
initial velocity uy = 0
acceleration = g =9.8 m/s2
height h =15 m
time t is taken to reach the water surface
using the second equation of motion
h = uy t + (1/2)gt2
15 = 0 + (0.5)(9.8)t2
15 = 4.9 t2
t2 = 3.06
t = 1.75 s
During this time the distance covered in horizontal direction is
x = vxt
x = 23 (1.75)
x = 40.3 m
He should search at a distance of 40.3 m far from bridge
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