A 0.1-kg ball is attached to the end of an ideal spring having a force constant (spring constant) of 600 N/m.
If the spring is compressed 18 cm and released, what is the speed of the ball when it reaches a distance of 12 cm from the equilibrium position?
Determine the period.
Determine the amplitude.
Determine the maximum speed.
Determine the total energy.
here,
mass , m = 0.1 kg
spring constant , K = 600 N/m
Amplitude , A = 18 cm = 0.18 m
let the speed be v1 when x1 = 0.12 m
using conservation of energy
0.5 * K * A^2 = 0.5 * K * x1^2 + 0.5 * m * v1^2
600 * 0.18^2 = 600 * 0.12^2 + 0.1 * v1^2
solving for v1
v1 = 10.4 m/s
the period , T = 2 * pi * sqrt(m/K)
T = 2 * pi * sqrt(0.1/600)
T = 0.081 s
the amplitude is 18 cm
the maximum speed , vm = A * w
vm = 0.18 * sqrt(600/0.1)
vm = 13.9 m/s
the total energy , TE = 0.5 * K * A^2
TE = 0.5 * 600 * 0.18^2 = 9.72 J
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