Question

A computer is reading data from a rotating CD-ROM. At a point that is 0.0375 m from the center of the disk, the centripetal acceleration is 330 m/s2. What is the centripetal acceleration at a point that is 0.0715 m from the center of the disc?

Answer 1

Angular speed of the CD-ROM =

Distance of the first point from the center of the disk = R1 = 0.0375 m

Centripetal acceleration of the first point = a1 = 330 m/s2

= 93.8 rad/s

Distance of the second point from the center of the disk = R2 = 0.0715 m

Centripetal acceleration of the second point = a2

a2 = 629 m/s2

Centripetal acceleration of a point 0.0715 from the center of the disk = 629 m/s2