A 13.5 Ω resistor is made from a coil of copper wire whose total mass is 14.0 g .
What is the diameter of the wire?
How long is the wire?
Given:
R = 3.5 ohm
M = 14 g = 14 x 10-3 kg
Note that the resistivity of copper wire is approximately to
ohm-cm
And the density of the copper wire is
Den = 8.94 g/cm3 .
Hence
Den = Mass / Volume
Volume = Mass / Density
Volume = 14 / 8.94
Volume = 1.565 cm3
In simple way, we can say that
Volume = Area x length
V = AL
A = V/L
As we also know that the resistance of the wire is given by:
Putting the value of A in the equation, we get
L2 = (R x Volume) ÷ (Rho)
L2 = (13.5 x 1.56 ) ÷ (1.68 x 10-6)
L = 3547.37 cm
L = 3.547 m
using again
A = Volume / Length
3.1415 x r2 = 1.565/3547.37
r = 0.01183 cm
Diameter is equal to
D = 2 x 0.01183
D = 0.0236 cm
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