You drop a 2.7 kg book to a friend who stands on the ground at distance D = 11 m below. If your friend’s outstretched hands are at distance d = 1.5 m above the ground (see the figure). If the gravitational potential energy U of the book–Earth system is taken to be zero at ground level, what is U when it reaches her hands?
**Consider all base units SI** **Do not use exponential numbers**
Solution : The gravitational potential energy when the book reaches har hand = mgh where m= mass =2.7kg
, h = height of the book from the ground = 1.5 m
g =acceleration due to gravity .= 9.8m/s^2
So the potential energy = 2.7×1.5×9.8 =39.69 J
Answer = 39.69 J
Note: you haven't uploaded the figure. So I have solved the problem from my imagination of the figure . If you find that answer is not correct then post the problem again with proper figure.
Thank you.
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