Question

1, Two charges are placed on the x axis. One of the charges (q1 = +8.09C) is at x1 = +3.00 cm and the other (q2 = -21.5C) is at x2 = +9.00 cm. Find the net electric field (magnitude and direction given as a plus or minus sign) at (a) x = 0 cm and (b) x = +6.00 cm.

2. Two charges, -22 C and +3.5 C, are fixed in place and separated by 3.0 m. (a) At what spot along a line through the charges is the net electric field zero? Give the distance of the spot to the positive charge in meters (m). (Hint: The spot does not necessarily lie between the two charges.) (b) What would be the force on a charge of +14 C placed at this spot?

Answer #1

1 )

q_{1} = + 8.09 C

x_{1} = + 3.00 cm = 0.03 m

q_{2} = - 21.5 C

x_{2} = +9.00 cm = 0.09 m

a )

at x = +3.00 cm

E = - k q_{1} / 0.03^{2} + k q_{2} /
0.09^{2}

E = - 9 X 10^{9} ( 8.09 / 0.03^{2} + 21.5 /
0.09^{2} )

**E = - 1.047 X 10 ^{14} N/C**

b )

at x = +6.00 cm

E = k q_{1} / 0.03^{2} + k q_{2} /
0.09^{2}

E = 9 X 10^{9} ( 8.09 / 0.03^{2} + 21.5 /
0.03^{2} )

**E = 2.959 X 10 ^{14} N/C**

2 )

a )

given

q_{1} = -22 C = | -22 | = 22 C

q_{2} = +3.5 C = | + 3.5 | = 3.5 C

d = 3.0

here E_{1} = E_{2}

kq_{1} / ( d +x )^{2} = kq_{2} / ( x
)^{2}

q_{1} / ( d +x )^{2} = q_{2} / ( x
)^{2}

x = q_{2}^{2} / q_{1}^{2} +
q_{2}^{2}

x = d / ( ( q_{1}/ q_{2} )^{1/2} + 1
)

x = 3 / ( 22/3.5 )^{1/2} + 1

x = 0.855 m

**at x = 0.855 m the net electric field zero**

b )

**if the force on a charge of +14 C placed at this spot is
also the force is ZERO.**

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(a) Number ______ Units_____
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1.
Two charges are placed on the x axis. One of the charges (q1 =
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given as a plus or minus sign) at (a) x = 0 cm and (b) x = +6.00
cm.
(a) Number Units (b) Number Units
2.
Check Your Understanding: Question 18.17
Drawings A and B show two examples...

Two charges are placed on the x axis. One of the
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