Question

A transformer has 840 loops in its secondary winding and is designed to accept an input AC potential difference of 760 V and produce an output of 380 V. How many loops does the transformer’s primary winding contain?

Answer 1

Here we are given that ,

Number of loops in secondary winding N2 = 840

Number of loops in primary winding N1 = to be find

Input AC potential difference Vi = 760 V

Output AC potential difference Vo = 380 V

So for the loops that the transformer’s primary winding contain will be given by the transformation ratio of transformer that is given as

Vi/Vo = N1/N2

So that on plugging the value we will get,

N1 = Vi/Vo × N2 = 760/380 × 840 = 1680

Which is our required answer.