Question

A ray of light strikes a flat, 2.00 cm thick block of glass (n = 1.50) at an angle of 30° with the normal as shown in the figure .The light ray is shifted laterally by a distance d . Find the value of d.

Answer 1

see the diagram :

For a given pair of angles the ratio of sine of the angles is constant for a given pair of medium.

i = angle of incidence = 30o.

r = angle of refraction = ?

e = angle of emergence = i = 30o.

d = lateral displacement = ?

n = refractive index = 1.5

t = thickness of glass slab = 2cm.

Applying Snell's Law at the surface of first refraction :

also, we can detremine ,

From the traingle ABC,

we can calculate AC :

From the traingle ACD :

angle CAD = i - r = 30 - 19.47 = 10.53o.

Also, [answer]