Question

A 3970 kg demolition ball swings at the end of a 34.4 m cable on the arc of a vertical circle. At the lowest point of the swing, the ball is moving at a speed of 2.08 m/s. Determine the tension in the cable.

Answer #1

Given that the mass of ball is m = 3970 kg

length of the cable is L = 34.4 m

Speed of the ball is v = 2.08 n/s

----------------------------------------------

At bottom of the swing, weight mg acts downwards

centripetal force mv^{2}/L acting downwards.

tension acting upwards.

Then from Newton's second law

T =
mg + mv^{2}/ L

=
3970kg*9.8 m/s^{2} + 3970kg*(2.08 m/s)^{2} / 34.4
m

= 39146 N

Please rate if it is correct

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