Question

The angular displacement from the neutro position of a pendulum at large angles affect its time period. What would be the steps for this investigation?

Answer #1

A simple pendulum oscillates back and forth with a maximum
angular displacement of pi/12 radians. At t=1.2s, the pendulum is
at its maximum displacement. The length (L) of the pendulum is 35cm
and the mass (m) of the bob attached to the end of it is 300g.
(a) What's the angular frequency of this oscillation?
(b) What's the angular position as a function of time?
(c) What's the angular speed as a function of time?
(d) If damping is introduced...

(1) A simple pendulum oscillates back and forth with a maximum
angular displacement of θMax “ (pi/12) radians. At t = 1.2s, the
pendulum is at its maximum displacement. The length of the pendulum
is L = 35cm and the mass of the bob attached to the end of it is m
= 300g.
(a) What is the angular frequency of this oscillation?
(b) What is the angular position as a function of time?
(c) What is the angular speed...

Use the Buckingham Pi theorem to find the angular displacement
of theta of a pendulum as a function of time (t) as well as its
initial angular position theta knot. The pendulum, has a mass m and
a length of rope L. To apply the theorem, you will also need the
gravity (g). Please explain in detail why you got the answer you
did. I'm aware this answer if already on Chegg however it got a
thumbs down.

A simple pendulum of length L = 1 m oscillates with
its angular displacement as function of time given by
θ(t)=10°cos(πt ‒ π/2). At time t = 2T/3, where T is the period of
oscillation, the values the velocity and tangential acceleration
are:
v = ‒ (√3/2) v_max , and a_t = ‒ (1/2) a_max
v = 0, and a_t = ‒ a_max
v = ‒ (1/2) v_max ), and a_t = + (√3/2) a_max
v = (√3/2) v_max ,...

At a time of 2.00 ✕ 102 s after starting its SHM from
maximum displacement, a mass on a spring has a displacement that is
+2.90 cm from the equilibrium position. If the frequency of the SHM
is 2.74 Hz, what is the amplitude of the SHM?

A simple pendulum with mass m = 2 kg and length L = 2.67 m hangs
from the ceiling. It is pulled back to an small angle of θ = 11°
from the vertical and released at t = 0.
1)What is the period of
oscillation?
s
2)What is the magnitude of the
force on the pendulum bob perpendicular to the string at
t=0?
N
3)What is the maximum speed of
the pendulum?
m/s
4)What is the angular
displacement at...

The time period of a simple pendulum is directly related to the
square root of its length. An 8-foot pendulum has a period of 3.2
seconds. Round all answers off to the nearest hundredth. Find the
period for each of these:
a. A grandfather clock that has a pendulum of length 3 feet.
b. A mantle clock that has a pendulum of length 6 inches.
c. The longest pendulum in the world whose length was 4440
feet.
d. If you...

What is the angular displacement of a wheel that accelerates
from rest to 6 rad/s with an angular acceleration of 2
rad/s2?

At t=0 the current to a dc electric motor is reversed, resulting
in an angular displacement of the motor shaft given by ?(t)=( 247
rad/s )t?( 19.7 rad/s2 )t2?( 1.54 rad/s3 )t3.
A)At what time is the angular velocity of the motor shaft
zero?
B)Calculate the angular acceleration at the instant that the
motor shaft has zero angular velocity.
C)How many revolutions does the motor shaft turn through between
the time when the current is reversed and the instant when...

a) If you take a simple pendulum to moon and Venus, how its time
period will be affected if its length is 80 cm?
b) If you decrease the length of the pendulum to half of the
original and increase mass to double of original, what will happen
to its period on Earth?
c) If an oscillating spring system is taken to the moon, what
will happen to its periods?
d) If the length of the spring is doubled, what...

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