Question

Find the period of a child's leg as it swings
about the hip joint. Assume the leg is 0.39 m long and can be treated as a uniform rod.

. s

Estimate the child's walking
speed.

m

help me?

Answer #1

(1) ? ~= sin (?)

Then we can use the simple harmonic motion model for the leg.
Additionally, the leg is an example of a compound pendulum, where
the rod is not massless and may have any shape.

From ref 1, the equation for the period T of a compound pendulum is
given by:

(2) T = 2 * ? * ? (I / (m * g * Lcm) )

where:

Lcm = the distance from the pivot point to the center of mass =
0.39 / 2 = 0.195m

and

(3) I = the moment of inertia of a uniform-mass rod pivoting about
one of its ends (see ref. 2)

= m * Lr^2 / 3,

where Lr is the length of the rod = 0.39m

Substituting the above into (2):

(4) T = 2 * ? * ? (I / (m * g * Lcm) )

= 2 * ? * sqrt ( (m * Lr^2 / 3) / (m * g * Lr/2) )

= 2 * ? * sqrt ( (Lr^2 / 3) / (g * Lr/2) )

= 2 * ? * sqrt ( (Lr / 3) / (g / 2) )

= 2 * ? * sqrt ( (2 * Lr ) / ( 3 * g ) )

= 2 * 3.14 * sqrt ( (2 * 0.39 ) / ( 3 * 9.81 ) )

T = 0.9998 so let's just call it 1.00s . . . . . .<<<===
period of one complete oscillation (forth and
back)

Next, the child's walking speed V:

(5) V = Distance / Time

How much distance does the child cover during one period?
Experiment with this: It turns out that, for one leg to go through
one cycle it requires two strides (or steps).

Each step is ? radians, so, continuing (5)

= 2 steps * ? rad/step * 0.37m/rad / 1s

= ? * 0.74 m/s . . . the child's estimated walking speed

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