Question

Two resistors, with resistance R1= 5 ohms and R2=25 ohms are connected in series in a circuit. The current flow generates heat at a rate of 1280 J/s in R1. What is the voltage drop across R2?

Answer 1

Resistance of the first resistor = R₁ = 5

Resistance of the second resistor = R₂ = 25

Current in the first resistor = I₁

Current in the second resistor = I₂

Rate at which heat generated by the first resistor = P₁ = 1280 J/s

I₁ = 16 A

The resistors are connected in series therefore the current through the resistors is the same.

I₂ = I₁

I₂ = 16 A

Voltage drop across the second resistor = V₂

V₂ = I₂R₂

V₂ = (16)(25)

V₂ = 400 V

Voltage drop across R₂ = 400 V