In a quarter-mile drag race, two cars start simultaneously from rest, and each accelerates at a constant rate until it either reaches its maximum speed or crosses the finish line. Car A has an acceleration of 10.6 m/s2 and a maximum speed of 104 m/s. Car B has an acceleration of 11.7 m/s2 and a maximum speed of 87.5 m/s. (a) Which car wins the race? (b) By how many seconds does this car win the race?
d = 1609/4 = 402.25 m
For Car A:
during accelerated motion:
vf = vi + a t
104 = 0 + 10.6 t1
t1 = 9.811 sec
distance travelled in this time, d1 = v0 t + at^2 /2
d1 = 510.2 m
so it will cross the distance during this time.
402.25 = 0 + 10.6 t^2 /2
tA = 8.712 sec
For car B:
t1 = 87.5 / 11.7 = 7.48 sec
87.5^2 - 0^2 = 2(11.7) (d1)
d1 = 327.2 m
d2 = d - d1 = 75.05 m
t2 = 75.05 / 87.5 = 0.858 sec
tB = t1 + t2 = 8.34 sec
hence car B will win race: .......Ans
(B) delta(t) = tA - tB = 0.374 sec .......Ans
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