In the circuit shown in the diagram below, two thick wires connect a 1.7 volt battery to a Nichrome (NiCr) wire. Each thick connecting wire is 15 cm long, and has a radius of 9 mm. The thick wires are made of copper, which has 8.36e+28 mobile electrons per cubic meter, and an electron mobility of 0.00434 (m/s)/(V/m). The Nichrome wire is 6 cm long, and has a radius of 5 mm. Nichrome has 9e+28 mobile electrons per cubic meter, and an electron mobility of 7e-05 (m/s)/(V/m).
1.What is the magnitude of the electric field in the thick copper wire?
2.What is the magnitude of the electric field in the thin Nichrome wire?
given
V = 1.7 V
thick wire
L = 15 cm
R = 9 mm
N = 8.36*10^28 per m^3
M = 0.00434 m/s / V/m
nichrome wire
l = 6 cm
r = 5 mm
n = 9*10^28
m = 7*10^-5
1. from ohms law
E = J/sigma
now, for thick wire
sigma = eNM = 1.722*10^-8
resistance
R = rho*L/pi*R^2 = 1.105*10^-5 ohm
hence
E1 = V"/R
2. from ohms law
E2 = J/sigma'
now, E = V'/l
also, R' = (1/sigma')l/A = 7.5788*10^-4 ohm
hence Reff = 2R + R' = 7.799*10^-4 ohm
henceE1 = V*R/Reff*L = 0.1605 V/m
E2 = V*R'/Reff*l = 27.5333 V/m
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