a paintball gun supplies a force of 65 N on a 0.024kg
pellet for 0.41m. ignoring the effects of air resistance, how high
would the pellet reach if it was shot straight forward?
please show work
Answer:
Given, Force F = 65 N, mass of the pellet m = 0.024 Kg and distance the pellet experienced dl = 0.41m.
When a paintball gun supplies a force F on a pellet m for a distance dl, there is an acceleration and work done takes place.
Work done W = F.dl = (65 N) (0.41m) = 26.65 J. The work will convert into kinetic energy K = mv2/2. i.e., W = K.
and then at the point of maximum height K will convert into Potential energy U, that means at maximum height, kinetic energy K = 0 and U = mgh becomes maximum.
Therfore, W = U = mgh, which implies that height h = U/mg = (26.65 J) / (0.024 kg) (9.8 m/s2) = 113.3 m.
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