A hollow right angle cylinder of radius a and length L has both ends and the sides grounded except for a band in the middle of the side of the cylinder. The band in the middle is held at a potential of V0 and extends from the center of the side of the cylinder for a distance of L/4 in both directions. a) Find the potential everywhere inside the cylinder. b) Find the charge density on the surface of the cylinder.
(a) Inside the hollow cylinder, E = q/2pie0 r H , for r > R where q is the charge, R is the radius of the cylinder, H is the height of the cylinder, e0 is epsilon0 . therefore, potential V will be
V = L [ E. dr] , where L is the integral, dr is the infinitesimal change in the radius
V = Lr0 [ q/2pie0r H dr] = 0r[q x logr /2pie0 H] = q x logr/2pie0H - q/2pie0H
V = q/2pie0H [ logr - 1]
(b) Surface charge density, s will be
V = 1/4pie0 L[s/ r]
also, V = q/2pie0 H [ log r - 1]
q/2pie0 H [logr - 1] = 1/4pie0 L[s/r]
2q/H [logr -1] = L[s/ r]
d[ 2q/H [logr -1]/dr = s/r
2q/H x 1/r = s/r
s = 2q/H .
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