Question

2. A soccer player kicks a ball toward a wall 64 m away with velocity 34 m/s at 61.93 degree above the horizontal. Assume g = 10 m/s^2. Ignore air resistance

(a) determine how high up the opposite wall the ball hits, and find the impact, velocity.

(b) the ball bounces back toward the kicker . Assume the horizontal component of the velocity flip direction (sign) but that the direction (sign) of the vertical velocity is unchanged. Determine where the ball hits the ground. Does the ball land between kicker and wall or does it land behind the kicker?

(c) Make a sketch of the trajectory of the ball. At two times (one before it hits the wall and one after), sketch velocity and acceleration vectors

Answer 1

(a) From the equation of trajectory, we can get the height as

(b) Final vertical velocity on hitting the wall

So when the ball rebound from the wall, the initial velocity in the x-direction is u cos(61.93) in opposite direction and the initial vertical velocity is as calculated above in downward direction.

the distance is given by

So the ball land between kicker and wall.

c)