Question

A particle moving in the xy-plane has velocity v⃗ =(2ti+(3−t2)j)m/s, where t is in s. What...

A particle moving in the xy-plane has velocity v⃗ =(2ti+(3−t2)j)m/s, where t is in s.

What is the x component of the particle's acceleration vector at t = 7 s?
What is the y component of the particle's acceleration vector at t = 7 s?

Science   Physics   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

Dear student|

[ ] If you have any query regarding this solution, don't forget to comment I will immediately sort it out.and if you are satisfied and find helpful then KINDLY GIVE THE RATING .your rating is very important to me.

Thanks for asking ||

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
The velocity v of a particle moving in the xy plane is given by v =...
The velocity v of a particle moving in the xy plane is given by v = (7.0t -4.0t2 )i + 7.5j, in m/s. Here v is in m/s and t (for positive time) is in s. What is the acceleration when t = 3.0 s? i-component of acceleration? j-component of acceleration? When (if ever) is the acceleration zero (enter time in s or 'never')? When (if ever) is the velocity zero (enter time in s or 'never')?
The acceleration of a particle moving only on a horizontal xy plane is given by a→=3ti^+4tj^,...
The acceleration of a particle moving only on a horizontal xy plane is given by a→=3ti^+4tj^, where a→ is in meters per second-squared and t is in seconds. At t = 0, the position vector r→=(19.0m)i^+(44.0m)j^ locates the particle, which then has the velocity vector v→=(5.40m/s)i^+(1.70m/s)j^. At t = 4.10 s, what are (a) its position vector in unit-vector notation and (b) the angle between its direction of travel and the positive direction of the x axis?
A particle with a charge of −1.24E-8 C is moving with instantaneous velocity v⃗  = (4.19E4 m/s)(i)...
A particle with a charge of −1.24E-8 C is moving with instantaneous velocity v⃗  = (4.19E4 m/s)(i) + (−3.85E4 m/s )(j). What is the force exerted on this particle by a magnetic field B= (1.50 T ) (i)? Forces in x, y, and z. What is the force exerted on this particle by a magnetic field B= (1.50 T ) (k)? Forces in x, y, and z. Please show ALL work.
The acceleration of a particle moving only on a horizontal xy plane is given by ModifyingAbove...
The acceleration of a particle moving only on a horizontal xy plane is given by ModifyingAbove a With right-arrow equals 4t ModifyingAbove i With caret plus 5t ModifyingAbove j With caret, where ModifyingAbove a With right-arrow is in meters per second-squared and t is in seconds. At t = 0, the position vector ModifyingAbove r With right-arrow equals left-parenthesis 24.0mright-parenthesis ModifyingAbove i With caret plus left-parenthesis 49.0mright-parenthesis ModifyingAbove j With caret locates the particle, which then has the velocity vector...
A particle is constrained to travel along a path on the xy-plane. r_x=(4t^4)m and r_y=2(sqrt(x)) where...
A particle is constrained to travel along a path on the xy-plane. r_x=(4t^4)m and r_y=2(sqrt(x)) where t is in seconds(rx and ry are the direction vectors of the particle), determine the magnitude of the particle's velocity and acceleration when t=0.5s
A particle with a charge of −1.24×10−8C is moving with instantaneous velocity v⃗ = (4.19×104m/s)i^ +...
A particle with a charge of −1.24×10−8C is moving with instantaneous velocity v⃗ = (4.19×104m/s)i^ + (−3.85×104m/s)j^ . Part A What is the force exerted on this particle by a magnetic field B⃗  = (1.40 T ) i^? Enter the x, y, and z components of the force separated by commas. Part B What is the force exerted on this particle by a magnetic field B⃗  = (1.40 T ) k^? Please solve and show how you get the z component from...
The velocity-time graph of a particle moving along the x-axis is shown. The particle has zero...
The velocity-time graph of a particle moving along the x-axis is shown. The particle has zero velocity at t = 0.00 s and reaches a maximum velocity, vmax, after a total elapsed time, ttotal. If the initial position of the particle is x0 = 7.29 m, the maximum velocity of the particle is vmax = 11.3 m/s, and the total elapsed time is ttotal = 25.0 s, what is the particle's position at t = 16.7 s? b. At t...
) A particle is moving according to the velocity equation v(t) = 9t^2-8t-2 . The equation...
) A particle is moving according to the velocity equation v(t) = 9t^2-8t-2 . The equation uses units of meters and seconds appropriately. At t = 1 s the particle is located at x = 2 m. (a) What is the particle's position at t = 2 s? (b) What is the particle's acceleration at t = 1 s? (c) What is the particle's average velocity from t = 2 s to t = 3 s?
A fish swimming in a horizontal plane has velocity i = (4.00 + 1.00 ) m/s...
A fish swimming in a horizontal plane has velocity i = (4.00 + 1.00 ) m/s at a point in the ocean where the position relative to a certain rock is i = (16.0 − 1.80 ) m. After the fish swims with constant acceleration for 17.0 s, its velocity is = (23.0 − 1.00 ) m/s. (a) What are the components of the acceleration of the fish? ax = m/s2 ay = Review the definition of average acceleration and...
A particle of mass m=0.2kg moves in the xy plane subject to a force such as...
A particle of mass m=0.2kg moves in the xy plane subject to a force such as that its position as a function of time is given by the vector r(t)= (3.0m/s2)t*2i+[12.0m-(2.0m/s*3)t*3]j what is the magnitude of the torque on the particle about the origin at the moment when the particle reaches the x axis?
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT