You create a plot of voltage (in V) vs. time (in s) for an RC circuit as the capacitor is charging, where V=V_{0} \cdot \left(1- e^{ \frac{-\left(t\right)}{RC} } \right). You curve fit the data using the inverse exponent function Y=A \cdot \left(1- e^{-\left(Cx\right)} \right)+B and LoggerPro gives the following values for A, B, and C. A = 4.611 ± 0.4211 B = 0.1599 ± 0.007211 C = 1.951 ± 0.2051 What is the time constant and its uncertainty?
NEED CORRECT SIGNIFICANT DIGITS.
IT IS NOT 0.5222+/- 0.05388 s
I TRIED THIS ALREADY.
I hope you understood the problem, If yes rate me!! or else comment for a better solution.
Get Answers For Free
Most questions answered within 1 hours.