Question

A uniform solid brass cylinder of mass 0.50 kg and radius of 0.030 m starts to rotate about its cylinder axis with an angular velocity of 60 rad/s.

a. What is the angular momentum of the cylinder and how much work is required to reach this rate of rotation, starting from rest?

b. After the cylinder has reached 60 rad/s, it is heated up from room temperature (20^oC) to 100^oC. The mean coefficient of linear expansion of brass is 2.0 x 10^-5 1/C^o. What is the angular velocity after it is heated? What is the fractional change in angular velocity?

c. What is the angular momentum after it is heated? Explain why.

d. What is the kinetic energy after it is heated?

Answer 1

(A) I = M R^2 /2

I = (0.50) (0.03^2) /2

I = 2.25 x 10^-4 kg m^2

w = 60 rad/s

L = I w = 0.0135 kg m^2 / s .....Ans

(B) R = R0 (1 + alpha deltaT)

R = 0.03 ( 1 + (2 x 10^-5)(100-20))

R = 0.030048  

Applying angular momentum conservation,

I w = I' wf

wf =I w / I'

delta(w) = w - wf = w ( I' - I) / I'

= 60 ( R^2 - R0^2) / R^2
= 60 ( 2 alpha deltaT )

= 60 x 2 x 2 x 10^-5 x 80

= 0.192 rad/s

(c) angular momentum will be same as before.

(d) KE = (0.50 x 0.030048^2 / 2) (60 - 0.192)^2 / 2

= 0.4037 J