When ultraviolet light with a wavelength of 400 nm falls on a certain metal surface, the maximum kinetic energy of the emitted photoelectrons is 1.10 eV .
What is the maximum kinetic energy K_0 of the photoelectrons when light of wavelength 340 nm falls on the same surface?
Use h = 6.63×10^{−34} J⋅s for Planck's constant and c = 3.00×10^{8} m/s for the speed of light and express your answer in electron volts.
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K_0 = 

eV 
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