What is the minimum horizontal force that will cause a 5.00-kg box to begin to slide on a horizontal surface when the coefficient of static friction is 0.710? (Express your answer to three significant figures.)
Gravitational acceleration = g = 9.81 m/s2
Mass of the box = m = 5 kg
Coefficient of static friction = = 0.71
Normal force on the box from the horizontal surface = N
N = mg
Maximum friction force on the box = f
f = N
f = mg
Minimum horizontal force so that the box begins to slide = F
For the box to start sliding the minimum force must overcome the maximum friction force.
F = f
F = mg
F = (0.71)(5)(9.81)
F = 34.8 N
Minimum force that will cause the box to slide = 34.8 N
Get Answers For Free
Most questions answered within 1 hours.